(2m+18)^2+(3m)^2=m^2

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Solution for (2m+18)^2+(3m)^2=m^2 equation: 



(2m+18)^2+(3m)^2=m^2

We move all terms to the left:

(2m+18)^2+(3m)^2-(m^2)=0

determiningTheFunctionDomain
3m^2-m^2+(2m+18)^2=0

We add all the numbers together, and all the variables

2m^2+(2m+18)^2=0

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